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Grade: 12 

                        
if Cu2+/Cu electrode is decreased 10 times then what will be the chamge in reduction potentiol?
3 years ago

Answers : (1)

Shailendra Kumar Sharma
188 Points 
							
Cu+2 +2e → Cu

Eold=Eo + (0.0591/2) log (Cu+2)
with the decrease in concentration by Cu+2/10
Enew=Eo + (0.0591/2) log (Cu+2/10)
       = Eo + (0.0591/2) log (Cu+2)-(0.0591/2)log10
       =Eold – 0.0295
 
3 years ago
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