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if Cu2+/Cu electrode is decreased 10 times then what will be the chamge in reduction potentiol? if Cu2+/Cu electrode is decreased 10 times then what will be the chamge in reduction potentiol?
Cu+2 +2e → CuEold=Eo + (0.0591/2) log (Cu+2)with the decrease in concentration by Cu+2/10Enew=Eo + (0.0591/2) log (Cu+2/10) = Eo + (0.0591/2) log (Cu+2)-(0.0591/2)log10 =Eold – 0.0295
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