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`        How to find change in enthalpy in  such typ of que1.i f the the pressure is constant change in enthalpy should eqeal heat transfer q as p∆v will get strike out. In constant volume p∆v is already going to be 0and enthalpy should eqeal q+v∆p but sir iIam not getting answer please correct my concect`
9 months ago

Rajdeep
231 Points
```							 HELLO THERE!  There are some important points to consider for answering this question. dH = U + PdVWe also know that:dH = TdS + VdPAgain, Heat (q) = TdS So, dH = q + VdPHence for constant pressure, (dP = 0), heat of a reaction is equal to the change in enthalpy (dH). One more thing to note:From First Law of Thermodynamics, we have:dq = du – dw = du – PdVFor constant volume, dV = 0, so q =dU. In the above question, we have to calculate the heat of the reaction at constant Volume, which is equal to the Change in Internal Energy.dH = dU + d(PV)or, dU = dH – $\dpi{100} \triangle$nRT Change in moles = Moles of product – Moles of reactant = 6 – 7.5 = -1.5 R = 1.98 cal/mol K = 2 cal/mol KSo, dU = -780980 + (1.5 x 2 x 298) = 894 – 780980 cal = -780086 cal THIS MUST BE YOUR ANSWER...Thanks!
```
9 months ago
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• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions