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Grade 12Physical Chemistry

Find Ksp of CaCl2 , if Λmc=x Scm2 mol-1 and K (kappa )=0.001 S cm -1 at 298 K

Profile image of krishna priya
9 Years agoGrade 12
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1 Answer

Profile image of Bhavya
ApprovedApproved Tutor Answer9 Years ago
We know that
\Lambda= (K * 1000)/ solubility
Applying the values we get,
solubility = (0.001 * 1000)/x = 1/x
Now,
CaCl2 ---------> Ca+2 + 2Cl-
s 2s
Ksp = s*(2s)2 =4s3
= 4/x3