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```        Equal weights of methane and oxygen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by oxygen is
a. 1/3
b. 1/2
c. 2/3
d. 1/3  ×  273/298
```
5 years ago

396 Points
```							Sol.  If x g of both oxygen and methane are mixed then :
Mole of oxygen = x/32
Mole of methane = x/16
⇒ mole fraction of oxygen = (x/32)/(x/32  + x/16)  =  1/3
According to law of partial pressure
Partial pressure of oxygen (po2) = mole-fraction × total pressure
⇒  〖Po〗_2/p  =  1/3

```
5 years ago
Shivani singh
15 Points
```								Suppose the mass of methane as well as oxygen =w=1	(Xo2) = w/32/w/32+w/16 = 1/32/3/32 = 1/3 	Let the total pressure = p 	Pressure exerted by oxygen =  Xo2 × Ptotal =	P× 1/3
```
one year ago
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### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions