Mass of K
2SO
4, w = 25 mg = 0.025g (use 1 g = 1000 mg )
Volume V = 2 liter
T = 25 + 273 = 298 K
The reaction of dissociation of K2SO4
K
2SO
4 → 2K+ + SO
42-Number if ions produced = 2+ 1 = 3
So van’t Hoff factor i = 3
Now

Substituting the values and calculationg we get,
π= 5.27 × 10
-3 atm