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Calculate the wave number for the shortest wavelength transition in the Balmer series of atomic hydrogen.

Calculate the wave number for the shortest wavelength transition in the Balmer series of atomic hydrogen.

Grade:11

2 Answers

Aditi Chauhan
askIITians Faculty 396 Points
9 years ago
The shortest wavelength transition in the Barlmer series corresponds to the transition
n = 2 → n = ∞. Hence, n1 = 2, n2 = ∞ Balmer
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ankit singh
askIITians Faculty 614 Points
3 years ago

 

The shortest wavelength transition inn the balmer series corresponds to the transiton n1​=2,n2​=∞.
 
For hydrogen spectrum,
 
Wave number, νˉ or λ1​=RH​[n1​21​−n2​21​]
 
Putting the values and we get,
 
νˉ=27425 cm−1

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