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        Calculate the volume of Xe which could be isolated from 1000km3 sample air at standard temperature and pressure conditions,if the amount of Xe in the atmosphere is 0.076? Please explain with reasons..
one month ago

Arun
23382 Points
							Dear studentVolume v of air is 1000km3=1*10^12 m3.Standard temperature, T=273.15KStandard pressure P is 101325Pa.0.076g of Xe will have (0.076/131.29) moles=5.789*10^-5.The volume of 0.076g of xe is  7.6*10^-5/5.761=1.319*10^-5Volume of Xe in 1000km3 is given by;P/TRn=VV=nRT/PV= (5.789*10^-4) *8.314* 273.15/101325v =1.297*10^-5m3Hope it helps

13 days ago
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