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Calculate H+ in 0.20 M solution of dichloroacetic acid that contains 0.1 M sodium dichloroacetate. Neglected hydrolysis of sodium salt
CHCl2COOH CHCl2COO– + H+ CHCl2COONa CHCl2COO– + Na+ Ka =22[CHCl COO ][H ][CHCl COOH] 5 × 10–2 =(0.1 0.2 )(0.2 )0.2(1 ) 21 = 1(1 2 ) 1 – = 2 + 42 42 + 3 –1 = 0 =8 3 9 16 = 8 3 5 = 82 = 0.25 [H+] = 0.2 = 0.2 × 0.25 = 0.5
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