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amit singh Grade: 11
        And what I do for improving understanding in physical chemistry such as in equilibrium
one year ago

Answers : (5)

Piyush Kumar Behera
199 Points
										
Its very clear to improve your understanding you must be conceptually strong  
then you should move on to problems.Remember!!
for concepts you can follow books like GRB,etc.
For problems some good books are of author like of n avasti,r.c. mukharje,etc
coaching materials are also useful.
to master the concept use a strategy to solve problems.
Hope  it helps!!Please approve!!
one year ago
Umakant biswal
5362 Points
										
dear amit 
ionic equilibrium part is important for jee , so, for understanding u need to start with besic books like ncert and make sure u understand everything well from ncert . 
and after ncert go with askiitians video lecture and self study package , they will explain u everything conceptwise . 
then take no of mock test to get the mastery on that topics . 
HOPE IT CLEARS 
ALL THE BEST 
REGARDS 
one year ago
Piyush Kumar Behera
199 Points
										
@Umakant Biswal
I dont agree what you are saying because i dont think so only askiitians video lecture and self study package and mock test is enough for mastering the topic because ionic equilibrium is a topic which needs a lot of variety of good problems written by experienced and good authors like r.c.mukharjee 
and n avasti ,etc.I think you dont know about this.That is why you are suggesting only askiitians sudy materials over these book.Only posting answers in counselling areas and not in subject related topics will help you no way.Try to go through these books in your spare time.
one year ago
amit singh
10 Points
										show that on the axis of the parabola there is a certain point k which has the property that if a chord PQ of the parabola passes through it then 1/PK^2+1/QK^2 is constant
										
one year ago
Dweepayan Biswal
47 Points
										
 What ould be the …
Date: 30/05/2017/F-4062/A2417-3
Answer:
4
h
    x P

7 9
4 10
22
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p

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  9
4 10
h
p 
 

2
p meV  2
h
p
  2
h
p
p
   
34 34
31 19 9
6.626 10 6.626 10
2 9.1 10 1.6 10 6 4 10
 
  
 

     
11 6.282 10 
8 months ago
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