Grade 12Physical Chemistry
What is the second excitation energy of li+2? (1) 12.09ev (2) 48.36ev (3) 108ev (4) 51ev
What is the second excitation energy of li+2?
(1) 12.09ev (2) 48.36ev (3) 108ev (4) 51ev
1 Answer
Brotha
The formula for the energy of the electron in n^th orbit is En = -13.6Z^2/n^2 eV.
So, for the first orbit (n=1), E1 = -13.6*(3)^2/(1)^2 = -122.4 eV [Here, Z = 3]
For second orbit, n = 2, E2 = -13.6*(3)^2/(3)^2 = -13.6 [Here, Z = 3]
The second excitation energy of Li^2+ is the energy when an electron jumps from the first orbit (n = 1) to the third orbit (n = 3), = E2 – E1 = −13.6− (−122.4) =108 eV
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