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A vessel containing gas at a pressure of 60 cm of Hg was connected to arm A of open end manometer. The atmospheric pressure was recorded as 74 cm of Hg. If the mercury in arm A stands at 84.5 cm height,the mercury in arm B will stand at

Arun
25763 Points
2 years ago
Dear Namit

I am getting my answer as 70.5 cm

Please let me know, if this is correct then I will share my solution

Regards
Arun
snehal
13 Points
2 years ago
arun,answer shi hai pr bnae kaise ho?? btao plzz,
hum bhi yhi question puche the kuch der pehle
Prachi kumari
15 Points
one year ago
Let the height of Mercury in arm B is p.
In the given question,  Pressure of atmosphere is greater than the pressure of Mercury.
So,  74= 60+(84.5-p)
p=70.5 cm.....