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A vessel containing gas at a pressure of 60 cm of Hg was connected to arm A of open end manometer. The atmospheric pressure was recorded as 74 cm of Hg. If the mercury in arm A stands at 84.5 cm height,the mercury in arm B will stand at

A vessel containing gas at a pressure of 60 cm of Hg was connected to arm A of open end manometer. The atmospheric pressure was recorded as 74 cm of Hg. If the mercury in arm A stands at 84.5 cm height,the mercury in arm B will stand at
 

Grade:12th pass

3 Answers

Arun
25750 Points
5 years ago
Dear Namit
 
I am getting my answer as 70.5 cm
 
Please let me know, if this is correct then I will share my solution
 
Regards
Arun
snehal
13 Points
4 years ago
arun,answer shi hai pr bnae kaise ho?? btao plzz,
hum bhi yhi question puche the kuch der pehle
bta do bhai answer
Prachi kumari
15 Points
4 years ago
Let the height of Mercury in arm B is p. 
In the given question,  Pressure of atmosphere is greater than the pressure of Mercury. 
So,  74= 60+(84.5-p) 
        p=70.5 cm..... 

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