MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        A metal crystallises in two phases,  fcc and bcc,  whose unit cell lengths are 3.5 Armstrog and 3.0 Armstrong respectively.  The ratio of density of fcc and bcc is?
7 months ago

Answers : (3)

Adarsh
763 Points
							
Dear Sai,
the answer will be 1.259 .  Use the formula for density, = z.M/Na.a3. .
Thanks and Regards
Adarsh
7 months ago
Khimraj
2164 Points
							
Density is given by
d = (z*M)/(a3*NA)
given that a1 = 3.5 A0 and a2 = 3.0 A0
No of atom per unit cell of fcc z1 = 4
No of atom per unit cell of fcc z2 = 2
Sonratio of density of fcc and bcc
d1/d2 = (z1/z2)*(a2/a1)3 = (4/2)*(3/3.5)3 = 2*(6/7)3 =432/343.
Hope it clears. If you like answerthen please approve it.
7 months ago
Anjali kumari
99 Points
							
As density= Z..M/Na.a^3. You will get 432:343.If you like the answer please approve it.Thank you. Gusto do TCP go gdp cpc
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 276 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details