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Grade: 12
        A metal crystallises in two phases,  fcc and bcc,  whose unit cell lengths are 3.5 Armstrog and 3.0 Armstrong respectively.  The ratio of density of fcc and bcc is?
one year ago

Answers : (3)

Adarsh
763 Points
							
Dear Sai,
the answer will be 1.259 .  Use the formula for density, = z.M/Na.a3. .
Thanks and Regards
Adarsh
one year ago
Khimraj
2654 Points
							
Density is given by
d = (z*M)/(a3*NA)
given that a1 = 3.5 A0 and a2 = 3.0 A0
No of atom per unit cell of fcc z1 = 4
No of atom per unit cell of fcc z2 = 2
Sonratio of density of fcc and bcc
d1/d2 = (z1/z2)*(a2/a1)3 = (4/2)*(3/3.5)3 = 2*(6/7)3 =432/343.
Hope it clears. If you like answerthen please approve it.
one year ago
Anjali kumari
104 Points
							
As density= Z..M/Na.a^3. You will get 432:343.If you like the answer please approve it.Thank you. Gusto do TCP go gdp cpc
9 months ago
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