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Grade: 12

                        

a first order reaction takes 16 minutes for 50 % completion. how much time will it take for 75% completion

3 years ago

Answers : (1)

Souvik Mukherjee
50 Points
							
first we have to find out the rate constant of the reaction i.e. K
 
So, for qa 1st order reaction K=(1/16)X2.303X log[a/(a-50a/100) where a is the initial substrate concentration.
i.e. K= (1/16) X 2.303 X log 2
i.e. K= (1/16) X 0.693
i.e. K= 0.043
 
Now, we have to find out the time required for 75% completion
 
t=(1/0.043)X2.303X log[a/(a-75a/100)
t=(1/0.043)X2.303X log 4
t=(1/0.043) X 2 X 2.303 X log 2
t=(1/0.043)X 2 X 0.693
t=32.23min or 32 min
 
Thanks
Souvik Mukherjee
M.Sc. Chemistry, IIT Hyderabad
3 years ago
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