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A blackish brown coloured solid ‘A’ when fused with alkali metal hydroxides in presence of air, produces a dark green coloured compound ‘B’, which on electrolytic oxidation in alkaline medium gives a dark purple coloured compound C. Identify A, B and C and write the reactions involved.

Jayant Kumar , 12 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To tackle this question, let’s break down the information provided and identify the compounds step by step. The solid ‘A’ you’re referring to is likely a form of copper(II) oxide, which is a blackish-brown solid. When it reacts with alkali metal hydroxides in the presence of air, it forms a dark green compound ‘B’, which is probably a copper(II) hydroxide complex. Upon electrolytic oxidation in an alkaline medium, this compound transforms into a dark purple compound ‘C’, which is likely to be a copper(II) complex such as copper(II) oxide or a related species. Let’s delve into the reactions involved.

Identifying the Compounds

Compound A: Copper(II) Oxide

Compound A is copper(II) oxide (CuO), a blackish-brown solid. It is known for its ability to react with bases.

Compound B: Copper(II) Hydroxide Complex

When copper(II) oxide reacts with an alkali metal hydroxide (like sodium hydroxide, NaOH) in the presence of air, it forms a dark green compound, which can be represented as:

  • CuO + 2 NaOH + H2O → Cu(OH)2 + Na2O

In this reaction, the copper(II) oxide reacts with sodium hydroxide and water to form copper(II) hydroxide, which can appear as a dark green precipitate.

Compound C: Copper(II) Complex

Upon electrolytic oxidation of the copper(II) hydroxide in an alkaline medium, we can produce a dark purple compound. This can be represented as:

  • Cu(OH)2 + 2 e⁻ → Cu + 2 OH⁻
  • Cu + 2 OH⁻ + O2 → Cu(OH)2 (in presence of air)

However, during the oxidation process, the copper can form various complexes, and one of the common products is a copper(II) complex that appears dark purple, such as copper(II) tetraamine complex.

Summary of Reactions

To summarize, the sequence of reactions can be outlined as follows:

  • CuO + 2 NaOH + H2O → Cu(OH)2 (dark green compound B)
  • Electrolytic oxidation: Cu(OH)2 → Cu complex (dark purple compound C)

In conclusion, the compounds identified are:

  • A: Copper(II) oxide (CuO)
  • B: Copper(II) hydroxide (Cu(OH)2)
  • C: Copper(II) complex (dark purple)

This sequence illustrates the transformation of copper compounds through chemical reactions, showcasing the fascinating interplay between oxidation states and complex formation in inorganic chemistry.

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