2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?

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Amit Sahoo · Answer

W=p(ext)×∆vW=1×(10-8). {P(ext)=p(atm)=1atm}W=8L-atm. {or 8×101.33=810.64 Joule}Here pressure given is not the external pressure and hence pressure acting is only the atmospheric pressure and I.e. 1atm....

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2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?

2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?

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2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?

2 L of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 L. How much work is done in the expansion?

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