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find out the percentage of the reactant molecules crossing over the energy barrier at 325 K, given that ΔH 325 =0.12kcal, E a(backward) =+0.02kcal. give the detailed solution.

find out the percentage of the reactant molecules crossing over the energy barrier at 325 K, given that ΔH325=0.12kcal, Ea(backward)=+0.02kcal.


give the detailed solution.

Grade:12

1 Answers

Sheershak
8 Points
6 years ago


 Thus, percentage of molecules with energy greater than or equal to activation energy is 80.6%

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