2.2g of a compopund of phosphorous and sulphur has1.24g of P in it Determine its empirical formula

Dear pallavi

percentage of sulpher = 1.24/2.2 *100 =56.4

percentage of P = 100-56.4 =43.6

relative number of molecules  of S = 56.4/32 = 1.76

relative number of molecules  of P = 43.6 /31 = 1.41

intigral ratio of sulpher is =5

intigral ration of P   = 4

so imperical formula  = P₄S₅

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