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The normality of a solution gives the number of gram equivalents of the solute present in one litre of the solution

Number of gram equivalent of solute= Mass of solute in gram/equivalent weight of solute

Equivalent weight of solute (E)= Molar mass of solute/Valence factor

Valence factor forbase= acidity of base

Valence factor foracid= basicity of acid

Valence factor forelement= valency

Thus, if one gram equivalent of a solute is present in one litre of the solution, the concentration of the solution is said to beone normal.

1N = Normal = One gram equivalent of the solute per litre of solution = Normality is 1

N/2= Seminormal = 0.5 g equivalent of the solute per litre of solution = Normality is 0.5

N/10= Decinormal = 0.1 g equivalent of the solute per litre of solution = Normality is 0.1

N/100= Centinormal = 0.01 g equivalent of the solute per litre of solution = Normality is 0.01

N/1000= Millinormal = 0.001 g equivalent of the solute per litre of solution = Normality is 0.001