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first of all the na+ion will not be present at the corner while it can be said that na+ion is lost from one of he octahedral voids of one face then
the formula will become Na7Cl8
in nacl sructure na+ ion will occupy the tetrahedral voids while the cl-ion will occupy the fcc latice
total no. of octahedral voids in fcc latice is =4
given by [1/2*6(of the corner atoms i.e the centre of each face)+ 1(centre octahedral void along body diagonal)]
thus if the na +ion is lost fromone of the corner then the total no.of na+ion is {1/2(6-1)+1}=7/2 and no. of cl-ion =4 therefore the formula is Na7Cl8
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