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In the given diagram electronic transition is shown for the H-atom.

the transition of electron takes place from 4^th to 1^st orbit in all the possible ways.

In the given transition max wavelength is :

(1)

(2)

(3)

(4)

anto frederick , 12 Years ago

Grade 12

1 Answers

Sunil Kumar FP

the relation between the electronic transition interms of wavelength is given by
1/lambda =Rh*Z^2(1/n1^2 -1/n2^2)
for the hydrogen atom the atomic number is 1
therefore the wavelength will be maximum when n1 and n2 maximum
n2 max=5 and n1 mx=4
1/lambda =Rh(1/16 -1/25)
lambda =25*16/9)*Rh
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