MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
J Ravi Kiran Grade: 11 
        
What is the closest distance of approach of an Alpha paricle of energy 6MeV to a Gold nucleus (Z=79)?
8 years ago

Answers : (1)

Ramesh V
70 Points
										
   


Alpha scattering by gold 


This graph shows the energy in MeV of an alpha particle at distances r from a gold nucleus, 


Z = 79. 




5702-41_5850_untitled.JPG


From graph for 6Mev . distance is arnd 3*10-14m


--


regards


Ramesh
8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Physical Chemistry

The equivalent weight of Cu 3 P in Cu 3 P + Cr 2 O 7 –2 → Cu +2 + H 3 PO 4 + Cr +3 is Answer & Earn Cool Goodies
A compound was found to contain 5.37 nitrogen. What is the minimum molecular weight of the compound Answer & Earn Cool Goodies
Are there any tesrs to distinguish glucose & fructose?
Calculate the pH of a solution obtained by dissolving 490 mg H2SO4 in water so that the total volume...
If mole fraction of the solvent in a solution decreases then what happened to vapour pressur,boiling...
View all Questions »
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details