A Sample of an ideal gas is expanded 1 m^3 to 3 m^3 in a reversible process for which P=KV^2,with K=6 bar/m^6.work done by the gas is

Dear Rajat,

first converting all the parameters in SI units, i.e. unit of constant, K = 6 bar/m^6

1 bar = 10^5 N/m^2, => K = 6X10^5 N/m^8

so we can find out work from the equation,

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Rohith Gandhi P

thanks rohith bhaiya.but p is not equal yo K/V^2.you had solved it that way.but anyways i get the answer .Thanks a lot!!!!!!!!!!!!11i wish u help me in near future too.

if u still want some answer then integrate KV^2dV limits fron 1 to 3