5.6 L of helium gas at STP is adiabatically compressed to 0.7 L.

Taking the initial temp. to be t1 work done in the process is________

Question

5.6 L of helium gas at STP is adiabatically compressed to 0.7 L. Taking the initial temp. to be t1 work done in the process is________

Chetan Mandayam Nayakar · Answer

let P1,V1,T1 be initial values and P2,V2,T2 be final values. T1*(V1)^(&gamma;-1)=T2*(V2)^(&gamma;-1), &gamma;=5/3,P1*((V1)^&gamma;)=P2*((V2)^&gamma;) work done= (P2V2-P1V1)/(&gamma;-1)

ABHISHEK GAKHAR · Answer

give answer as a function of t1

Suraj Negi · Answer

Answer : 9/8RT1

HP · Answer

hint?

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5.6 L of helium gas at STP is adiabatically compressed to 0.7 L. Taking the initial temp. to be t1 work done in the process is________

5.6 L of helium gas at STP is adiabatically compressed to 0.7 L.

Taking the initial temp. to be t1 work done in the process is________

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