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OTP to be sent to Change
5.6 L of helium gas at STP is adiabatically compressed to 0.7 L.
Taking the initial temp. to be t1 work done in the process is________
let P1,V1,T1 be initial values and P2,V2,T2 be final values. T1*(V1)^(γ-1)=T2*(V2)^(γ-1), γ=5/3,P1*((V1)^γ)=P2*((V2)^γ)
work done= (P2V2-P1V1)/(γ-1)
give answer as a function of t1
Answer : 9/8RT1
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