 # Cu+ is not stable and undergoes disproportion. E for cu+ disproportionation.(E°  cu2+/cu =0.153V , E°  cu+/cu=0.53V).(a)  +0.683 V(b)  -0.367 V(c) +0.3415 V(d) +0.367 V 13 years ago

I want th make a small correction to question

Its cu2+/cu+ =0.153V  i.e.,                     cu2+ + e-   ------>  cu+            E0 = 0.153 V

Now going into problem

Cu+ solutions, tend to give a disproportion reaction:
2Cu+ ----- >   Cu + Cu2+

cu+ + e-    ------>  cu                                E0 = 0.53 V        so,  nE0 = 0.53 V

cu+            ------>  cu2+ + e-               E0 = - 0.153 V       so,  n E0 = - 0.153 V

on adding above rxns we get
2Cu+ ----- >   Cu + Cu2+                  with  E0 = +0.377 V

Option is D

2 years ago
The relationship between standard gibbs energy change for a reaction and its cell potential is ΔGo=nFEcello.

For copper electrodes,

ΔGCu2+Cuo=ΔGCu2+Cu+o+ΔGCu+Cuo

nFECu2+Cuo=nFECu2+Cu+onFECu+Cuo

2×ECu2+Cuo=1×ECu2+Cu+o+1×ECu+Cuo

Substitute values in the above equation.

2×ECu2+Cuo=1×ECu2+Cu+o+1×ECu+Cuo

=0.153V+0.53V

ECu2+Cu=0.3415 V