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Cu+ is not stable and undergoes disproportion. E for cu+ disproportionation.

(E° cu2+/cu =0.153V , E° cu+/cu=0.53V).

(a) +0.683 V

(b) -0.367 V

(c) +0.3415 V

(d) +0.367 V

mustafa bandook wala , 15 Years ago
Grade 12
anser 2 Answers
Ramesh V

Last Activity: 15 Years ago

I want th make a small correction to question

Its cu2+/cu+ =0.153V  i.e.,                     cu2+ + e-   ------>  cu+            E0 = 0.153 V

Now going into problem

Cu+ solutions, tend to give a disproportion reaction:
2Cu+ ----- >   Cu + Cu2+

                       
                     cu+ + e-    ------>  cu                                E0 = 0.53 V        so,  nE0 = 0.53 V    

                     cu+            ------>  cu2+ + e-               E0 = - 0.153 V       so,  n E0 = - 0.153 V 

on adding above rxns we get   
 2Cu+ ----- >   Cu + Cu2+                  with  E0 = +0.377 V   

 

Option is D

ankit singh

Last Activity: 4 Years ago

The relationship between standard gibbs energy change for a reaction and its cell potential is ΔGo=nFEcello.
 
For copper electrodes,
 
ΔGCu2+Cuo=ΔGCu2+Cu+o+ΔGCu+Cuo
 
nFECu2+Cuo=nFECu2+Cu+onFECu+Cuo
 
2×ECu2+Cuo=1×ECu2+Cu+o+1×ECu+Cuo
 
Substitute values in the above equation.
 
2×ECu2+Cuo=1×ECu2+Cu+o+1×ECu+Cuo
 
                        =0.153V+0.53V
 
ECu2+Cu=0.3415 V

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