Pankaj
Last Activity: 10 Years ago
Hello Studnt,
This problem can be solved usingHenderson's Equation as follows
pOH = pKb+log[KCN]/[HCN]
Here we know that the number of moles of KCN and HCN are equal in the solution so,[KCN] =[HCN] and
We get,
pOH = pKb+log 1
or pOH =pKb= 4.7
Now,
pH =14-pOH = 14-4.7 = 9.30