Flag Physical Chemistry> Physical Chemistry...
question mark

The PKb of cycanide ion is 4.7.The pH of solution prepared by mixing 2.5moles of KCN and 2.5moles of HCN in water and making total volume upto 500ml is(1)9.30(2)7.30(3)10.30(4)8.30{{*plese explen*}}

Praveen Kumar beniwal , 13 Years ago
Grade
anser 1 Answers
Pankaj

Last Activity: 10 Years ago

Hello Studnt,
This problem can be solved usingHenderson's Equation as follows
pOH = pKb+log[KCN]/[HCN]
Here we know that the number of moles of KCN and HCN are equal in the solution so,[KCN] =[HCN] and
We get,
pOH = pKb+log 1
or pOH =pKb= 4.7
Now,
pH =14-pOH = 14-4.7 = 9.30

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...