The PKb of cycanide ion is 4.7.The pH of solution prepared by mixing 2.5moles of KCN and 2.5moles of HCN in water and making total volume upto 500ml is(1)9.30(2)7.30(3)10.30(4)8.30{{*plese explen*}}
Praveen Kumar beniwal , 13 Years ago
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1 Answers
Pankaj
Last Activity: 10 Years ago
Hello Studnt, This problem can be solved usingHenderson's Equation as follows pOH = pKb+log[KCN]/[HCN] Here we know that the number of moles of KCN and HCN are equal in the solution so,[KCN] =[HCN] and We get, pOH = pKb+log 1 or pOH =pKb= 4.7 Now, pH =14-pOH = 14-4.7 = 9.30
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