Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Through what potential difference must an electron pass to have a wavelength of 500 angstrom.
Dear student, Calculate E=hc/wavelength Now E=eV Calculate potential difference...
Dear student,
Calculate E=hc/wavelength
Now E=eV
Calculate potential difference...
lamda = h/(2mVe)1/2 h = 6.6*10-34 , m = 9.1*10-31 , e = 1.6*10-19 lamda = wavelength = 500angstromes = 500*10-10m after substituting all these values we get V = 5.86*10-4 or 0.586 millivolts
lamda = h/(2mVe)1/2
h = 6.6*10-34 , m = 9.1*10-31 , e = 1.6*10-19
lamda = wavelength = 500angstromes = 500*10-10m
after substituting all these values we get
V = 5.86*10-4 or 0.586 millivolts
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -