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Through what potential difference must an electron pass to have a wavelength of 500 angstrom.


8 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

Calculate E=hc/wavelength

Now E=eV

Calculate potential difference...

8 years ago
vikas askiitian expert
509 Points
							

lamda  = h/(2mVe)1/2

 

h = 6.6*10-34 , m = 9.1*10-31 , e = 1.6*10-19

 

lamda = wavelength = 500angstromes = 500*10-10m

 

after substituting all these values we get

V = 5.86*10-4 or 0.586 millivolts

8 years ago
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