a sodium hydroxide solution contains 40% by weight of NaOH has specific gravity= 1.5. wat volume of this soln. is required to get 500 ml of .45M SOLUTION

40% by weight means , 40gm NaOH in 100 gm solution..

dincity of solution = 1.5                  (given)

volume of sol = 100/1.5  = 66.66ml  = 0.066L                          (dencity = mass/vol)

in 40gm NaOH no of moles = 40/M.wt = 40/40 = 1

molarity of sol = 1/0.066 = 15M/L

now we have M₂V₁ = M₂V₂

  15V = 0.45*500

   V =  15ml     ans

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