Grade 11Physical Chemistry

1 mol ferric oxalate is oxidized by x mol MnO4- and 1 mol ferrous oxalate is oxidized by y mol of MnO4- in acidic medium. Thr ratio x/y is ?

Ishika Ghosh

9 Years agoGrade 11

2 Answers

Vikas TU

8 Years ago

Dear Student,
From the chemical Reaction:

Fe2(C2O4)3 + MnO4 ===========>>> Mn2+ + CO2

The n factor of Fe2(C2O4)3 would thus be able to be taken as equivalent to the n factor of MnO4-

Along these lines

Reactant (n×nf) = Product (n×nf)

1×6= x×5

Along these lines x = (6/5)

Presently on account of ferrous oxalate Fe(C2O4)

Presently the new response can be composed as:

MnO4-+ FeC2O4 - Mn2+ +Fe3+ +CO2

Here additionally Mn is getting diminished from +7 oxidation state to +2 oxidation state.

Additionally in the compound, ferrous oxalate, Fe is in +2 oxidation state and C is in +3 oxidation state, which are getting changed to +3 and +4 resp.

So the aggregate n factor for the compound is 1+2=3

Again keeping the counterparts of the reactants and the items to be same on both the sides,

Y×5=1×3

Subsequently y = (3/5)

So the proportion, (x/y) will be (6×5)/(5×3)

= 2:1

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

Kushagra Madhukar

6 Years ago

Dear student,

Please find the attached solution to your problem.

The reaction taking place is

Fe₂(C₂O₄)₃ + MnO₄^- → Mn²⁺ + CO₂

The n factor of Fe₂(C₂O₄)₃ would thus be able to be taken as equivalent to the n factor of MnO₄^-

Along these lines

Reactant (n×nf) = Product (n×nf)

1×6= x×5

Along these lines x = (6/5)

Presently on account of ferrous oxalate Fe(C₂O₄)

Presently the new response can be composed as:

MnO₄^- + FeC₂O₄ → Mn²⁺ +Fe³⁺ +CO₂

Here additionally Mn is getting diminished from +7 oxidation state to +2 oxidation state.

Additionally in the compound, ferrous oxalate, Fe is in +2 oxidation state and C is in +3 oxidation state, which are getting changed to +3 and +4 resp.

So the aggregate n factor for the compound is 1+2 = 3

Again keeping the counterparts of the reactants and the items to be same on both the sides,

Y×5=1×3

Subsequently y = (3/5)

So the proportion, (x/y) will be (6×5)/(5×3)

= 2:1

Hope it helps.

Thanks and regards,

Kushagra