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The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1g of B solid is dissolved in 20g of A,its vapour pressure is reduced to 9 torr if the molecular mass of A is 200amu then the molecular mass of B is
Dear Student x2 = – p2/ pi = 1 / 10 = 0.1now x2 = [(m2 /M2) /(m1/ M1)]0.1 = [(1/M2) / (20/200)]M2 = 100 g mol-1 RegardsArun (askIITians forum expert)
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