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Grade 12Organic Chemistry

Calculate the molality of 2.5 of ethanoic acid in 75 gm of benzene

Profile image of Navya
4 Years agoGrade 12
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4 Answers

Profile image of Yuvraj Singh
4 Years ago
Answer
Profile image of Vijay
4 Years ago
Answer – 0.556 m 
 
Explaination – 
Molar mass of Ethanoic acid = 60g/mol
No. Of moles of ethanoic acid =                 GIVEN MASS                        
                                                             Molar mass / molecular mass     
   Therefore moles = 2.5/60 .
 
mass of solvent ( Bezene )  in kg = 75/1000  kg.
 
Molality = no. of moles of solute         
                  mass of solvent in KG 
 
 so after calculating we get Molality = 0.556
 
Thnaks
 
 
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3 Years ago

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3 Years ago

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