Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Calculate the molality of 2.5 of ethanoic acid in 75 gm of benzene

Calculate the molality of 2.5 of ethanoic acid  in 75 gm of benzene
 

Grade:12

2 Answers

Yuvraj Singh
askIITians Faculty 16 Points
one month ago
Answer
Vijay
100 Points
16 days ago
Answer – 0.556 m 
 
Explaination – 
Molar mass of Ethanoic acid = 60g/mol
No. Of moles of ethanoic acid =                 GIVEN MASS                        
                                                             Molar mass / molecular mass     
   Therefore moles = 2.5/60 .
 
mass of solvent ( Bezene )  in kg = 75/1000  kg.
 
Molality = no. of moles of solute         
                  mass of solvent in KG 
 
 so after calculating we get Molality = 0.556
 
Thnaks
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free