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Consider the following reaction and mark the in- correct statement CH3–C(OCH3)2–CH2–CH=O (1) In Wolff-Kishner reduction, the product formed is CH3–C(OCH3)2–CH2CH3 (2) With CH3MgBr followed by H3O+ treatment, the product formed is CH3COCH2CH(OH)CH3 (3) The reactant gives Tollen’s Test positive (4) In Clemmenson reduction, the product formed is CH3–C(OCH3)2–CH2CH3

Consider the following reaction and mark the in-
correct statement
CH3–C(OCH3)2–CH2–CH=O
(1) In Wolff-Kishner reduction, the product formed is CH3–C(OCH3)2–CH2CH3
(2) With CH3MgBr followed by H3O+ treatment, the product formed is CH3COCH2CH(OH)CH3
(3) The reactant gives Tollen’s Test positive
(4) In Clemmenson reduction, the product formed
is CH3–C(OCH3)2–CH2CH3

Grade:12

3 Answers

Adarsh
768 Points
6 years ago
Dear Samarvir ,
 
the correct option is 1 ,3 ,4 …. .. .. .. .. .. .. .. .. .. .. .. 
 
Thanks and Regards
Adarsh
Samarvir Jain
23 Points
6 years ago
Answer is 4th option because in presence of acid acetal group will leave off so 4th is incorrect and 2nd one is correct because in presence of acid acetals have leave off so carbonyl is formed
Arpita Panja
25 Points
6 years ago
Dear Samarvir,
 
2 and 4 are the incorrect statements....
Grignerd reagent acts as a base...so the reaction condition is basic...so only it should react with aldehyde..without affecting the metal gr..
During clemmenson reduction the reaction condition would be acidic..so ketal would be converted to Leto as ketal is unstable under acidic condition..and aldehyde would be reduced to CH2...     
Thanks                                                                                                                                                                        Arpita                                                                                                                                                  

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