Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The bisector of the acute angle between the lines 2 x -y - 4 =0 and X - 2y + +10=0 is

The bisector of the acute angle between the lines 2 x -y - 4 =0 and X - 2y + +10=0  is

Grade:11

1 Answers

Danish
16 Points
3 years ago
2x-y-4=0        eq-1
x-2y+10=0      eq-2
 
\frac{2x-y-4}{\sqrt{4+1}}=\pm \frac{x-2y+10}{\sqrt{1+4}}         eq. of angle bisectors
 
(If in this equation,
a1a2+b1b2>0 then -ve sign is for acute angle bisector and +ve sign is for obtuse angle bisector.
If, a1a2+b1b2
 
2*1+[-1*(-2)]     ( a1a2+b1b2)
=2+2
=4>0
 
so, we use -ve sign for acute angle bisector
2x-y-4=-(x-2y+10)
2x-y-4=-x+2y-10
3x-3y+6=0
x-y+2=0 is the required equation for acute angle bisector
 
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free