Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
How many unit cells are present in a cube shaped ideal crystal of NaCl of mass of 1g How many unit cells are present in a cube shaped ideal crystal of NaCl of mass of 1g
Dear student The number of Na+ ions present in one unit cell = 12×1/4 + 1 =4 atoms per unit cell.The number of Cl- ions present in one unit cell = 6×1/2 + 8×1/8 = 4 atoms per unit cell.So, each unit cell has 4 atoms of each Na+ and Cl-. Hence there are total 4 molecules of NaCl in each unit cell.As the mass of -Avogadro number of molecules- of NaCl is 58.5g.Then, number of molecules in one gram = 6.022× 10^23 ÷ 58.5 = 1.03×10^22 moleculesAs we found above that each unit cell contains 4 molecules of NaCl hence we can now easily find the number of unit cells containing 1.03×10^22 molecules = 1.03×10^22 ÷ 4 = 2.575×10^21 unit cellsSo, 2.575×10^21 unit cells contains 1gm of NaCl molecules.
The number of Na+ ions present in one unit cell = 12×1/4 + 1 =4 atoms per unit cell.
The number of Cl- ions present in one unit cell = 6×1/2 + 8×1/8 = 4 atoms per unit cell.
So, each unit cell has 4 atoms of each Na+ and Cl-. Hence there are total 4 molecules of NaCl in each unit cell.
As the mass of -Avogadro number of molecules- of NaCl is 58.5g.
Then, number of molecules in one gram = 6.022× 10^23 ÷ 58.5 = 1.03×10^22 molecules
As we found above that each unit cell contains 4 molecules of NaCl hence we can now easily find the number of unit cells containing 1.03×10^22 molecules = 1.03×10^22 ÷ 4 = 2.575×10^21 unit cells
So, 2.575×10^21 unit cells contains 1gm of NaCl molecules.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -