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PLEASE ANS THE QUESTION BRIEFLY AND TELL HOW TO APPROCH WITH FORMULAE
we know, separation between two faces of metal cube , l = side length = 1m Cross sectional area of metal cube , A = (1m)² = 1m²Force, F = 4.2 × 10^8 Nmodulus of rigidity of copper, Y = 14 × 10^10 Now, use formula, Young's modulus, Y = Fl/A∆l14 × 10^10 = 4.2 × 10^8 × 1/(1 × ∆l)∆l = 4.2 × 10^8/14 × 10^10 = 3 × 10^-3 mSo, lateral displacement of top surface, ∆l = 3 × 10^-3 m or 3mm
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