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How much charge is required for the following reductions of 1mol ol Al3+ to Al

sudhanshu , 12 Years ago
Grade 12
anser 1 Answers
Kamlesh Kumar
Al3+ + 3 e -----------> Al
1 mol 3 mol
3 faraday = 3 x 96500 = 289500 coulomb
i.e for deposition of one mol Al3+ 3 moles of electrons or 3 faraday or 289500 coulomb charge is
required


thanks &regards
Kamlesh Kumar
askIITians faculty
Last Activity: 12 Years ago
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