# Which of the following figures represent the variation of particle momentum and the associated de-Broglie wavelength?Correct ans is option 3Please ans with proper reasoning asap!

Umar Farooq
28 Points
3 years ago
This is something very straight-forward. de-Broglie wavelength is given by
$\lambda =h/p$
Where h=Planks constant
When you plot it, it resembles y=c/x graph
For p=1, $\lambda =h$
For p$\lambda > h$ (For example, if p=0.5, $\lambda=2h$)
For p>1, $\lambda(For example, if p=2, $\lambda=0.5h$)
As p tends to infinity, Wavelength tends to zero.