If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

Question

CHALLA NAVNEESWAR REDDY · Answer

given s=(4+6n) at t=n sec we know that, v=ut+1/2at 2 =(4+6n)=un+11/2an 2 , u=4+6n-1/2n 2 ,at t=0, initial velocity(u) =4m/sec a=(4+6n-un)2/t 2 , at t=0, acceleration(a)=0m/sec 2

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If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

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If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

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