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If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.
given s=(4+6n) at t=n secwe know that, v=ut+1/2at2=(4+6n)=un+11/2an2, u=4+6n-1/2n2,at t=0, initial velocity(u) =4m/seca=(4+6n-un)2/t2, at t=0, acceleration(a)=0m/sec2
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