Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

If the distance travelled by a body in nth second is (4+6n)m then find the initial velocity and acceleration of the body respectively.

Grade:9

1 Answers

CHALLA NAVNEESWAR REDDY
33 Points
4 years ago
given s=(4+6n) at t=n sec
we know that, v=ut+1/2at2
=(4+6n)=un+11/2an2,  u=4+6n-1/2n2,at t=0, initial velocity(u) =4m/sec
a=(4+6n-un)2/t2, at t=0, acceleration(a)=0m/sec2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free