Grade 12th passModern Physics

A carnot engine absorbs 400 J of heat from a reservoir at the temperature of water and rejects heat to a reservoir at triple point of water. the efficiency of the engine

Avinash mukhi

4 Years agoGrade 12th pass

1 Answer

sabu ram

4 Years ago

Heat absorbed, Q1=1000J

Heat rejected, Q2=600J

Temperature of reservoir, T1=127°C=127+273=400K

To find:

Efficiency of the engine, η=?

Temperature of sink, T2=?

Amount of useful work done per cycle, W=?

We know,

Efficiency of Carnot engine can be found be using the following formula,

η=Q1Q1−Q2=10001000−600=0.4 or 40%

Hence, the efficiency of the engine is 40%

We know, Efficinecy of carnot engine is also equal to

η=T1T1−T2∴0.4=400400−T2⟹400−T2=160⟹T2=400−160=240K or 240−273=−33°C

Hence, the temperature of the sink is -33°C.

We know,

W=Q1−Q2=1000−600=400J

Hence the amount of useful work done during each cycle is 400J.

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A carnot engine absorbs 400 J of heat from a reservoir at the temperature of water and rejects heat to a reservoir at triple point of water. the efficiency of the engine

Avinash mukhi

1 Answer

sabu ram

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