An energy of 24.6 ev is required to remove one electron from neutral Helium atom the energy required to remove both the electron is?

On removing an electron the Helium atom becomes a single electron atom, applying Bohr's Model ,the energy of the single electron is given by
-13.6z2n2 (where z is atomic no. and n is the no. of the shell in which the electron resides).
Thus ,
the energy comes out to be -13.641, which is -54.4.
So ,
the total energy required to remove both the electrons will be 24.6+54.4=79.0
Thanks & Regards
Aarti Gupta
askiitians Faculty

On removing an electron the Helium atom becomes a single electron atom, applying Bohr`s Model ,the energy of the single electron is given by -13.6z2n2 (where z is atomic no. and n is the no. of the shell in which the electron resides). Thus ,the energy comes out to be -13.641, which is -54.4. So ,the total energy required to remove both the electrons will be 24.6+54.4=79.0