what is the power output of a uranium reactor if it takes 30 days to use up 2kg of fuel and each fission gives 185mev of usable energy

21 Points
13 years ago

No of mole of uranium 235 in 2 kg = 2*1000/235= 8.51
Each fission gives 185 Mev which is  185 × 1.60× 10^-13 joules E = 296 × 10^-13 J
One mole gives 6.023×10^23 × E = 1.78×10^13 J

Therefore total energy released with 2 kg U-235= 8.51×1.78×10^13 = 1.517×10^14 J.

Power = energy/ time.

Since this energy is released over 30 days time = 30×24×60×60= 2592000s
Hence power output = 1.517×10^14/2.592×10^6 W
=5.85×10^7 W

Abhinandan
20 Points
7 years ago
No of mole of uranium 235 in 2 kg = 2*1000/235= 8.51Each fission gives 185 Mev which is 185 × 1.60× 10^-13 joules E = 296 × 10^-13 JOne mole gives 6.023×10^23 × E = 1.78×10^13 JTherefore total energy released with 2 kg U-235= 8.51×1.78×10^13 = 1.517×10^14 J. Power = energy/ time.Since this energy is released over 30 days time = 30×24×60×60= 2592000sHence power output = 1.517×10^14/2.592×10^6 W =5.85×10^7 W