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Grade upto college level Modern Physics

4000 A photon is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I2 molecule is 246.5 kJ/mol

(A) 8%

(B) 12%

(C) 17%

(D) 25%

Profile image of Amit Saxena
12 Years agoGrade upto college level
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2 Answers

Profile image of Aditi Chauhan
12 Years ago

(C)

 

Sol.   Energy of one photon =12400/4000

 

                                        = 3.1 ev

 

        Energy supplied by one ole photon in KJ/mole = 3.1 × 1.6 × 10–19 × 6 × 1023 × 10–3 = 297 kJmol–1

 

        % of energy converted to K.E. =  = 17%

Profile image of Krishi Patel
5 Years ago
Calculate the work function for metal for which ejection of the photoelectron can be stopped by applying 0.4  V  when the radiation of 300nm is used.