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In the nucleus of 11Na23, the number of protons, neutrons and electrons are
(a) 11, 12, 0
(b) 23, 12, 11
(c) 12, 11, 0
(d) 23, 11, 12
(a)
Z = 11 i.e., number of protons = 11, A = 23
\ Number of neutrons = A - Z = 12
Number of electron = 0 (No electron in nucleus)
Therefore 11, 12, 0.
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