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Obtain the amount of Co necessary to provide a radioactive source of 8.0 Ci strength. The half-life of Co is 5.3 years?

shreya , 11 Years ago
Grade 12
anser 1 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student,

lamda= ln2/half life
1 Ci=3.7 × 10^10 decays per second
half life=5.3*365*24*60*60=1.671408*10^8
dN/dt=lamda*N=8*3.7 × 10^10
=>N=8*3.7 × 10^10/lamda=8*3.7 × 10^10*1.671408*10^8/ln2 moles

Thanks & Regards
Arun Kumar
Askiitians Faculty
IIT Delhi

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