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# A semicircular wire has a length L and mass M. A particle of mass m is placed at the centre of the circle.find gravitational attraction on the particle due to the wire

Arun Kumar IIT Delhi
7 years ago
If we see only horizontal component will remain.
$dF=Gmsin(\theta)dM/R^2 \\=>dF=G*m*sin(\theta)M(Rd\theta)/L \\=>\int_{0}^{F} dF=GMm/R\int_{0}^{\pi}sin(\theta)d\theta \\=>F=GMm2/R$
Arun Kumar
IIT Delhi