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Dear Hari,
At point A, sin30o/sinr = 1/1.44
=> r = sin–1 (0.72) also ? BAD = 180o – ?r
In rectange ABCD, ?A + ?B + ?C + ?D = 360o => (180o – r) + 60o + (180o – r) + q = 360o => q = 2 [sin–1 (0.72) – 30o]
In rectange ABCD, ?A + ?B + ?C + ?D = 360o
=> (180o – r) + 60o + (180o – r) + q = 360o
=> q = 2 [sin–1 (0.72) – 30o]
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