0

Guest

Courses New

Two particles A and B are projrcted from the same point on the ground. Particle A is projecyed on a smooth horizontal surface with speed v, whereas B is projrcted with velocity 2v/√3. The two particles collide when the particle B drops on the surface for the first time. Find: a) The angle with which the particle B was projected into air. b) The separation between the two particles when B is at its highest position.

Two particles A and B are projrcted from the same point on the ground. Particle A is projecyed on a smooth horizontal surface with speed v, whereas B is projrcted with velocity 2v/√3. The two particles collide when the particle B drops on the surface for the first time.
Find:
a) The angle with which the particle B was projected into air.
b) The separation between the two particles when B is at its highest position.

Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Dear student,

Since the particle collide on the horizontal surface after finite time, their horizontal displacement must be same. Hence the horizontal component of their velocities must be same. Therefore\dfrac{2v}{\sqrt{3}}cos\theta=v\implies cos\theta=\dfrac{\sqrt{3}}{2}\implies \theta=30^{\circ}
When it is at maximum height, the separation is the height of the particle B which is equal to\dfrac{u^2sin^2{\theta}}{2g}=\dfrac{v^2}{6g}

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More