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`        two bikes A and B start from a point. A moves with uniform speed 40m/s and B starts from rest with uniform acceleration 2 m/s2. If B starts at t=0 and A starts from the same point at t=10s, then the time interval during the journey in which A was ahead of B is:	20s	8s	10s	A is never ahead of B`
8 months ago

Saurabh Koranglekar
3161 Points
```							Dear studentDistance ofA after 10 sec = 400 mDistance of B after 20 sec = 400 mspeed of A after 20 sec and 21 sec = 40 m/s , 40 m/sspeed of B after 20 sec and 21 sec = 40 m/s, 42 m/sDistance of A after 21 sec = 440 mDistance of B after 21 sec = 442 mTherefore A just managed to touch B but was never aheadhence optionDRegards
```
8 months ago
Dishari Das
16 Points
```							The answer provided to this question needs a change I.e. distance of A after 11 sec=440mPlease approve if this is correct .
```
8 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

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