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two bikes A and B start from a point. A moves with uniform speed 40m/s and B starts from rest with uniform acceleration 2 m/s 2 . If B starts at t=0 and A starts from the same point at t=10s, then the time interval during the journey in which A was ahead of B is: 20s 8s 10s A is never ahead of B

two bikes A and B start from a point. A moves with uniform speed 40m/s and B starts from rest with uniform acceleration 2 m/s2. If B starts at t=0 and A starts from the same point at t=10s, then the time interval during the journey in which A was ahead of B is:
  1. 20s
  2. 8s
  3. 10s
  4. A is never ahead of B

Grade:11

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
5 years ago
Dear student

Distance ofA after 10 sec = 400 m

Distance of B after 20 sec = 400 m

speed of A after 20 sec and 21 sec = 40 m/s , 40 m/s

speed of B after 20 sec and 21 sec = 40 m/s, 42 m/s

Distance of A after 21 sec = 440 m

Distance of B after 21 sec = 442 m

Therefore A just managed to touch B but was never ahead

hence optionD

Regards
Dishari Das
16 Points
5 years ago
The answer provided to this question needs a change 
I.e. distance of A after 11 sec=440m
Please approve if this is correct .

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