0

Guest

Courses New

The velocity of a particle moving on the x-axis is given by v = x^2 + x, where x is in m and v is in m/s. What is its position (in m) when its acceleration is 30m/s^2

The velocity of a particle moving on the x-axis is given by v = x^2 + x, where x is in m and v is in m/s. What is its position (in m) when its acceleration is 30m/s^2

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
accln. = vdv/dx = > (x^2 +x)*(2x + 1) = 30 
=> 2x^3 + x^2 + 2x^2 + x – 30 = 0
From Remainder tgeorem x = 2 satifies it.
one root is x = 2.
Now to find other roots,
a + b + 2 = -0.5
a + b = – 2.5
and 
2ab = 15
ab = 15/2
the eqn. becomes,
a + 15/2a = -2.5
a^2 + (5/2)a + 15/2 = 0
or
2a^2 + 5a + 15 = 0
It’s Discriminant is less than zero hence it has imaginafry roots.
Therefore.
the position is at x= 2 meter.

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More