Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

Grade:6

1 Answers

Heer Shah
19 Points
one month ago
component of mg towards incline =mgsin(q)
Where q is the angle of wedge
N=mgcos(q)
friction =0.3 N =0.3mgcosq
Net force towards incline =mgsin(q)-0.3mgcos(q)
 
a=gsin(q)-0.3gcos(q)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free