A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

Question

Heer Shah · Answer

component of mg towards incline =mgsin(q) Where q is the angle of wedge N=mgcos(q) friction =0.3 N =0.3mgcosq Net force towards incline =mgsin(q)-0.3mgcos(q) a=gsin(q)-0.3gcos(q)

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A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

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A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

A 20kg box sit on an inclined as illustrations shows , the coefficient of kinetic friction between the box and incline is 0.30,find the acceleration of the box down the incline.

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