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A particle moves along a straight line with its velocity related to position as v=-alpha x² (where alpha=constant) If at t=0 and v=0 then find the following i) Acceleration in terms of displacement ii) Acceleration in terms of time

A particle moves along a straight line with its velocity related to position as v=-alpha x² (where alpha=constant) If at t=0 and v=0 then find the following i) Acceleration in terms of displacement ii) Acceleration in terms of time

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1 Answers

Vibekjyoti Sahoo
145 Points
one year ago

Given x2=2+t Now differentiating this equation with respect to time we get ,

2xdtdx=1v=dtdx=2x1
Now again differentiating equation A with respect to dx we get vdxdv.dtdx=2x1dx
vdtdv=2x21
dtdv=2x21(2x1)=4x31  
 
 

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